What is the induction of a magnetic field in which a force of 0.05 N acts on a conductor with a current of 25 A?

| July 19, 2021 | education

What is the induction of a magnetic field in which a force of 0.05 N acts on a conductor with a current of 25 A? The length of the active part of the conductor is 5 cm. The directions of the induction and current lines are mutually perpendicular.

I = 25 A.

Famp = 0.05 N.

L = 5 cm = 0.05 m.

∠α = 90 °.

B -?

A conductor with a current in a magnetic field is acted upon by the Ampere force Famp, the value of which is determined by the formula: Famp = I * B * L * sinα. Where I is the current in the conductor, B is the magnetic induction of the field, L is the length of the active part of the conductor, ∠α is the angle between the direction of the current and the vector of magnetic induction B.

B = Famp / I * L * sinα.

B = 0.05 N / 25 A * 0.05 m * sin90 ° = 0.04 T.

Answer: the conductor is in a magnetic field with induction B = 0.04 T.



One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.