What is the induction of the coil if, at a current of 3A, the magnetic field energy of the coil is 1.8 J?

To calculate the induction of the coil, we use the formula E = Li2 / 2; here E is energy, L is inductance, i is current strength.

From it we express Li2 = 2E; L = 2E / i2;

Substitute the values and find the inductance L = 2 * 1.8J / (3A) 2 = 3.6J / 9A2 = 0.4H

Answer: 0.4G.



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