What is the internal energy of 14 moles of an ideal monatomic gas at 17 degrees?

These problems: ν (the amount of substance taken from the gas) = 14 mol; Т (absolute temperature) = 290 К (17 ºС).

Reference values: R (universal gas constant) = 8.31 J / (mol * K); i (the number of degrees of freedom of a monatomic gas) = 3.

The required internal energy of 14 mol of an ideal monatomic gas taken can be calculated by the formula: U = i / 2 * ν * R * T.

Let’s calculate: U = 3/2 * 14 * 8.31 * 290 = 50607.9 J ≈ 50.6 kJ.

Answer: The internal energy of 14 mol of the taken gas is 50.6 kJ.