What is the internal energy of 15 mol of a monatomic gas at a temperature of 28 c?
| December 2, 2020 | education
Given:
n = 15 mol
T = 28 ° C = 301 K
Find: U =?
Decision:
U = 3/2 * n * R * T
Where R = molar gas constant
R = 8.31 J / K * mol
U = 3/2 * 15 * 8.31 * 301 = 56 300 J
Answer? U = 56300 J.
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