What is the kinetic energy of a pigeon flying at a speed of 61 km / h? The mass of the pigeon is 400g.

Given:

m = 400 grams = 0.4 kilograms – the mass of the pigeon;

v = 61 kilometers per hour – the speed of the pigeon.

It is required to determine W (Joule) – the kinetic energy of the pigeon.

Let’s convert the units of measurement of speed from kilometers per hour to meters per second:

v = 61 km / h = 61 * 10/36 = 17 meters per second.

Then the kinetic energy of the pigeon will be equal to:

W = m * v ^ 2/2 = 0.4 * 17 ^ 2/2 = 0.4 * 289/2 = 0.2 * 289 = 57.8 Joules.

Answer: The pigeon has a kinetic energy of 57.8 Joules.