What is the largest two-digit number that is divided by 12 to get a remainder of 5.

Let the largest two-digit natural number x have such a value that when dividing it by the number 12, a remainder of 5 is obtained, that is, x: 12 = n (remaining 5), then x = 12 ∙ n + 5 where n ∈ N. The equation is obtained with two unknowns, the solution of which is found by selection, taking into account that 9 <x <100. Find n = 7, we get: x = 12 ∙ 7 + 5; x = 84 + 5; x = 89.
Answer: 89 is the largest two-digit number, which when divided by 12 is 5.