What is the length of a mathematical pendulum if the period of its oscillation is 2 s?

The oscillation period of a given mathematical pendulum can be described by the formula:

T = 2Π * √ (l / g), where T is the value of the oscillation period of the pendulum (T = 2 s), l is the sought length of the mathematical pendulum, g is the acceleration of gravity (constant, g = 9.81 m / s2) …

Let us express from the formula and calculate the length of the pendulum:

T / 2Π = √ (l / g).

(T / 2Π) 2 = l / g.

l = (T / 2Π) 2 * g = (2 / (2 * 3.14)) 2 * 9.81 ≈ 1 m.

Answer: The length of a given mathematical pendulum is 1 m.



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