What is the length of a mathematical pendulum that oscillates with a period of 1s.

The period of a mathematical pendulum can be found by the formula T = 2pi * square root (l / g), where pi = 3.14, l is the length of the pendulum, and g is the acceleration of gravity and is equal to 10 m / s ^ 2.
T = 1 s.
square root (l / 10) = 1 / 6.28
square root (l / 10) = 0.16
l / 10 = 0.256
l = 10 * 0.256
l = 2.56 m.
Answer: 2.56 m.



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