What is the length of a pendulum that oscillates harmonically at a frequency of 0.5 Hz on the surface of the moon?

| August 2, 2021 | education

What is the length of a pendulum that oscillates harmonically at a frequency of 0.5 Hz on the surface of the moon? The acceleration of gravity on the surface of the moon is 1.6 m / s2.

We take the formula for the oscillation period of a mathematical pendulum: T = 2 * 3.14 * root (l / g) where T is the period, l is the length of the pendulum, g is the acceleration of gravity. Where T = 1 / (frequency) we square everything and substitute the place for the letters of the number: 1 / (0.5) ^ 2 = 4 * (3.14) ^ 2 * l / 1.6. From here we find l. l = (1.6 ^ 2 * 1) / (0.5 ^ 2 * 4 * 3.14 ^ 2). Using even the most common calculator, you can calculate the answer. Answer: approximately 0.26 if the task was set to simplify to hundredths. If asked to simplify to tenths, the answer is 0.3.



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