What is the lifting height of a thrown ball if its potential energy has increased by 60 J? The mass of the ball is 300 g.

Given:

dE = 60 Joules – the amount by which the potential energy of the thrown ball has increased;

m = 300 grams is the mass of the ball;

g = 10 Newton / kilogram – acceleration of gravity.

It is required to determine h (meter) – the height to which the ball was thrown.

Let’s convert mass units from grams to kilograms:

m = 300 grams = 300 * 10-3 = 300/1000 = 0.3 kilograms.

Then, to determine the height of the ball, you need to use the following formula:

dE = m * g * h, from here we find that:

h = dE / (m * g) = 60 / (0.3 * 10) = 60/3 = 20 meters.

Answer: the ball was thrown to a height of 20 meters.