What is the likelihood that a mother who is a carrier of the gene for color blindness and a father

What is the likelihood that a mother who is a carrier of the gene for color blindness and a father who is color blind will have a healthy son?

Let’s designate the gene for color blindness h, respectively, healthy vision – H. it is indicated that the mother is a carrier of an abnormal trait, her genotype is XHXh (one of the chromosomes contains the gene for color blindness). The father is color blind, which means that his only X chromosome contains the h gene, his genotype is XhY. Parents’ gametes: XH, Xh and Xh, Y. As a percentage of the phenotype, such parents may have the following children: XHXh (25% female – carrier); XHY (25% healthy boy); XhXh (25% female – color blind); XhY (25% boy – color blind).



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