What is the m of the weight suspended on the spring if the stiffness coefficient is 800H \ m

What is the m of the weight suspended on the spring if the stiffness coefficient is 800H \ m and the spring elongation is 2 cm?

Given:

k = 800 Newton / meter – coefficient of spring stiffness;

dx = 2 centimeters = 0.02 meters – the amount of spring elongation;

g = 10 m / s2 – acceleration of gravity.

It is required to determine m (kilogram) – the mass of the load suspended from the spring.

Let’s find the force under which the spring is stretched:

F = k * dx = 800 * 0.02 = 16 Newtons.

This force is the force of gravity acting on the load suspended from the spring:

F = m * g, hence:

m = F / g = 16/10 = 1.6 kilograms.

Answer: The mass of the load suspended from the spring is 1.6 kilograms.