What is the magnetic flux through the solenoid, if at a current strength of 5A, the energy of its magnetic field is 5J?

Initial data: I (solenoid current) = 5 A, W (solenoid magnetic field energy) = 5 J.

Magnetic flux:

Ф = L * I, where L is the inductance of the solenoid.

Magnetic field energy:

W = L * I ^ 2/2.

Let us derive the formula for calculating the magnetic flux from these formulas.

L = 2W / I ^ 2 and Ф = 2W / I ^ 2 * I = 2W / I.

Let’s do the calculation:

Ф = 2 * 5/5 = 2 Wb.

Answer: The magnetic flux through a given solenoid is 2 Wb.