What is the mass fraction in% hydrochloric acid solution obtained by merging 100 ml of 28% hydrochloric

What is the mass fraction in% hydrochloric acid solution obtained by merging 100 ml of 28% hydrochloric acid solution (p = 1.18 g / ml) and 90 ml of 1.5 M solution (p = 1.03 g / ml)?

Given:
V1 solution (HCl) = 100 ml
ω1 (HCl) = 28%
ρ1 solution (HCl) = 1.18 g / ml
V2 solution (HCl) = 90 ml = 0.09 l
Cm2 (HCl) = 1.5 M
ρ2 solution (HCl) = 1.03 g / ml

Find:
ω3 (HCl) -?

1) m1 solution (HCl) = ρ1 solution * V1 solution = 1.18 * 100 = 118 g;
2) m1 (HCl) = ω1 * m1 solution / 100% = 28% * 118/100% = 33.04 g;
3) n2 (HCl) = Cm2 * V2 solution = 1.5 * 0.09 = 0.135 mol;
4) m2 (HCl) = n2 * M = 0.135 * 36.5 = 4.9275 g;
5) m2 solution (HCl) = ρ2 solution * V2 solution = 1.03 * 90 = 92.7 g;
6) m3 (HCl) = m1 + m2 = 33.04 + 4.9275 = 37.9675 g;
7) m3 solution (HCl) = m1 solution + m2 solution = 118 + 92.7 = 210.7 g;
8) ω3 (HCl) = m3 * 100% / m3 solution = 37.9675 * 100% / 210.7 = 18.02%.

Answer: Mass fraction of HCl is 18.02%.