What is the mass fraction of hydrochloric acid in a solution obtained by dissolving 11.2 liters

What is the mass fraction of hydrochloric acid in a solution obtained by dissolving 11.2 liters of hydrogen chloride in 1 liter of water?

Given:
V (HCl) = 11.2 l
V (H2O) = 1 L = 1000 ml

To find:
ω (HCl) -?

Decision:
1) n (HCl) = V (HCl) / Vm = 11.2 / 22.4 = 0.5 mol;
2) M (HCl) = Mr (HCl) = Ar (H) * N (H) + Ar (Cl) * N (Cl) = 1 * 1 + 35.5 * 1 = 36.5 g / mol;
3) m (HCl) = n (HCl) * M (HCl) = 0.5 * 36.5 = 18.25 g;
4) m (H2O) = ρ (H2O) * V (H2O) = 1 * 1000 = 1000 g;
5) m solution (HCl) = m (HCl) + m (H2O) = 18.25 + 1000 = 1018.25 g;
6) ω (HCl) = m (HCl) * 100% / m solution (HCl) = 18.25 * 100% / 1018.25 = 1.8%.

Answer: Mass fraction of HCl is 1.8%.