What is the mass of 84 liters of oxygen (O 2) under normal conditions?

univerkov | January 17, 2021 | education

Given:
V (O2) = 84 l
To find:
m (O2)
Decision:
n (O2) = V / Vm = 84 l / 22.4 l / mol = 3.75 mol
m (O2) = n * M = 3.75 mol * 32 g / mol = 120 g
Answer: 120 g.

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