What is the mass of a lead part, if 2800 J of heat was spent to heat it by 20 C.
| May 7, 2021 | education
Given: Δt (change in temperature of the considered lead part) = 20 ºС; Q (heat consumption for heating) = 2800 J.
Constants: Сс (specific heat capacity of lead) = 140 J / (kg * K).
To determine the mass of the lead part under consideration, we use the formula: Q = Cc * m * Δt, whence m = Q / (Cc * Δt).
Let’s calculate: m = 2800 / (140 * 20) = 1 kg.
Answer: A heated lead part has a mass of 1 kilogram.
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