What is the mass of a piece of ice with a volume of 500 cm3 if the density of ice is 900 kg / m3?

V = 500 cm3 = 0.0005 m3.

ρ = 900 kg / m3.

m -?

The density of a substance ρ is a scalar physical quantity equal to the ratio of the body mass m to the volume V occupied by it: ρ = m / V.

m = ρ * V.

Let’s convert the volume of ice in the units of the International SI system.

V = 1 m3 is the volume of a cube with a side a = 1 m.

The volume of the cube V is determined by V = a3.

V = 1 m * 1 m * 1 m = 100 cm * 100 cm * 100 cm = 1,000,000 cm3.

1 cm3 = 0.000001 m3.

V = 500 cm3 = 0.0005 m3.

m = 900 kg / m3 * 0.0005 m3 = 0.45 kg.

Answer: a piece of ice has a mass of m = 0.45 kg.