What is the mass of a tin spoon, if 5.45 kJ of heat was spent on heating it from 32 to the melting point and melting?

To calculate the value of the mass of the indicated tin spoon, we apply the formula: Q = λ * m + Сo * m * (tmelt – t0) and m = Q / (λ + Сo * (tm – t0)).

Variables and constants: Q – consumed heat (Q = 5.45 kJ = 5450 J); λ – beats heat of fusion (λ = 5.9 * 10 ^ 4 J / kg); Co – beats heat capacity (Co = 230 J / (kg * K)); tmelt – melting point (we take tmelt = 231.9 ºС ≈ 232 ºС); t0 is the initial temperature of the spoon (t0 = 32 ºС).

Calculation: m = Q / (λ + Сo * (tmelt – t0)) = 5450 / (5.9 * 10 ^ 4 + 230 * (232 – 32)) = 0.0519 kg = 51.9 g.

Answer: The mass of the indicated tin spoon is 51.9 kg.