What is the mass of air occupying a volume of 150 liters at a temperature of 15 ° C and a pressure of 150 kPa.

Given: p = 150,000 Pa; t = 15 ° C; V = 0.150 m ^ 3; m-?
Solution:
Let us write the equation of state for an ideal gas:
p * V = v * R * T, where p is pressure, V is volume, v is amount of substance, R is molar gas constant, T is gas temperature in Kelvin. Let us express from this equality the amount of substance: v = p * V / (R * T). We can find the mass by the formula: m = v * M, where M is the molar mass, then substituting the previous formula into the given one will receive: m = p * V * M / (R * T); substitute the numerical values and calculate: m = 150000 Pa * 0.150 m ^ 3 * 0.02904 kg / mol /(8.31 J / (mol * K) * 288K) = 0.27301 kg (T = t + 273; M- tabular value).
Answer: 0.27301 kg.