What is the mass of alcohol if, during its condensation at a temperature of 78 degrees Celsius

What is the mass of alcohol if, during its condensation at a temperature of 78 degrees Celsius, an amount of heat of 1200 kJ is released?

To calculate the value of the mass of the alcohol that has passed into a liquid state, we apply the formula: Q = Lc * m, from where we express: m = Q / Lc.

Constants and variables: Q – the amount of released heat (Q = 1200 kJ = 1.2 * 10 ^ 6 J); Lс – specific heat of condensation (Lс = 0.9 * 10 ^ 6 J).

Calculation: m = Q / Lc = 1.2 * 10 ^ 6 / (0.9 * 10 ^ 6) = 1.33 kg.

Answer: 1.33 kg of alcohol vapor turned into a liquid.



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