What is the mass of alcohol, if its condensation at a temperature of 70 ° C released the amount of heat 1200 kJ?

Initial data: Q (the amount of heat released during the condensation of alcohol) = 1200 kJ; the alcohol was at the condensation temperature.

Reference values: L (specific heat of condensation of alcohol) = 0.9 * 10 ^ 6 J / kg.

SI system: Q = 1200 kJ = 1200 * 10 ^ 3 J.

The desired mass of alcohol is determined from the formula: Q = L * m and m = Q / L.

Let’s make the calculations: m = 1200 * 10 ^ 3 / (0.9 * 10 ^ 6) = 1.33 kg.

Answer: The mass of alcohol is 1.33 kg.