What is the mass of alcohol that can be obtained by hydrating ethylene with a volume of 448 liters?

Let’s find the amount of ethylene substance C2H4.

n = V: Vn.

n = 448 L: 22.4 L / mol = 20 mol.

C2H4 + HOH = C2H5OH.

According to the reaction equation, there is 1 mol of C2H5OH per 1 mol of С2Н4. Substances are in quantitative ratios 1: 1.

n (C2H5OH) = n (C2H4) = 20 mol.

Let’s find the mass of С2Н5ОН according to the formula:

m = n × M,

M (C2H5OH) = 46 g / mol.

m = 20 mol × 46 g / mol = 920 g.

Answer: 920