What is the mass of aluminum (Al) in reaction with sulfur (S) if 0.1 mol of aluminum sulfide (Al2S3) is obtained?
September 26, 2021 | education
| Let’s write the reaction equation:
2Al + 3S (t) = Al2S3
By condition, the amount of aluminum sulfide substance:
v (Al2S3) = 0.1 (mol).
According to the reaction equation, 1 mol of Al2S3 is formed from 2 mol of Al, therefore:
v (Al) = v (Al2S3) * 2 = 0.1 * 2 = 0.2 (mol).
Thus, the mass of reacted aluminum is:
m (Al) = v (Al) * M (Al) = 0.2 * 27 = 5.4 (g).
Answer: 5.4 g.
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