What is the mass of aluminum chloride AlCl3 taken in an amount of 0.7 mol?

The mass of the substance is m = n × M, where n is the amount of the substance, M is the molar mass of the substance.

M (AlCl3) = Ar (Al) + 3 Ar (Cl) = 27 + 3 × 35.5 = 133.5 g / mol.

m (AlCl3) = 0.7 × 133.5 = 93.45 g.

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