What is the mass of aluminum oxide formed when burning 5.4 g of aluminum?

univerkov | May 24, 2021 | education

Reaction equation:

4Al + 3O2 = 2Al2O3;

define the chemical quantities:

n (Al) = m (Al): M (Al) = 5.4: 27 = 0.2 mol;

n (Al2O3) = n (Al): 2 = 0.2: 2 = 0.1 mol;

find the mass of aluminum oxide:

m (Al2O3) = n (Al2O3) * M (Al2O3);

M (Al2O3) = 2 * 27 + 3 * 16 = 102 g / mol;

m (Al2O3) = 0.1 * 102 = 10.2 g.

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