What is the mass of aluminum oxide, which will react with 29.4 g of sulfuric acid.

Given:
m (H2SO4) = 29.4 g

To find:
m (Al2O3) -?

1) Al2O3 + 3H2SO4 => Al2 (SO4) 3 + 3H2O;
2) n (H2SO4) = m / M = 29.4 / 98 = 0.3 mol;
3) n (Al2O3) = n (H2SO4) / 3 = 0.3 / 3 = 0.1 mol;
4) m (Al2O3) = n * M = 0.1 * 102 = 10.2 g.

Answer: The mass of Al2O3 is 10.2 g.



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