What is the mass of ammonium chloride obtained by the interaction of 3 mol of ammonia with hydrochloric acid?

1. Let’s compose the equation of interaction of ammonia with hydrochloric acid:
NH3 + HCl = NH4Cl;
2. according to the reaction equation, the amounts of ammonia and ammonium chloride are equal:
n (NH4Cl) = n (NH3) = 3 mol;
3.Calculate the mass of the obtained ammonium chloride:
m (NH4Cl) = n (NH4Cl) * M (NH4Cl);
M (NH4Cl) = 14 + 4 + 35.5 = 53.5 g / mol;
m (NH4Cl) = 3 * 53.5 = 160.5 g.
Answer: 160.5 g.