What is the mass of an aluminum ingot with a volume of 1.8 m ^ 3?
| May 23, 2021 | education
Initial data: V (volume of aluminum ingot) = 1.8 m ^ 3.
Reference data: ρ (aluminum density) = 2700 kg / m ^ 3.
The mass of a given aluminum ingot can be determined by the formula: m = ρ * V.
Let’s make a calculation: m = 2700 * 1.8 = 4 860 kg = 4 t 860 kg.
Answer: The mass of an aluminum ingot is 4 860 kg (4 t 860 kg).
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