What is the mass of an iron part if, when cooled from 200 to 20 degrees, an amount of heat equal to 20.7 kJ

What is the mass of an iron part if, when cooled from 200 to 20 degrees, an amount of heat equal to 20.7 kJ was released into the environment? The specific heat capacity of iron is 460 J / kg degrees

Initial data: t1 (temperature of the iron part before cooling) = 200 ºС; t2 (final cooling temperature of the iron part) = 20 ºС; Q (heat that was released into the environment) = 20.7 kJ = 20.7 * 10 ^ 3 J.

Reference data: by condition C (specific heat capacity of iron) = 460 J / (kg * ºС).

The mass of the iron part is determined from the formula: Q = C * m * (t1 – t2) and m = Q / (C * (t1 – t2)).

Calculation: m = 20.7 * 10 ^ 3 / (460 * (200 – 20)) = 0.25 kg or 250 g.

Answer: The weight of the iron part is 250 grams.