What is the mass of calcium chloride obtained by the interaction of 112 g of calcium oxide with hydrochloric acid?

CaO + 2HCl = CaCl2 + H2O
n (CaO) = m (CaO) / M (CaO)
M (CaO) = 40 + 16 = 56 (g / mol)
n (CaO) = 112/56 = 2 (mol)
n (CaO) = n (CaCl2) = 2 (mol)
m (CaCl2) = M (CaCl2) * n (CaCl2)
M (CaCl2) = 40 + 35.5 = 111 (g / mol)
m (CaCl2) = 2 * 111 = 222 (g)



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