What is the mass of copper hydroxide 2 obtained by the reaction of 16 g of sodium hydroxide and 16 g of copper sulfate 2?

2NaOH + CuSO4 = Cu (OH) 2 + Na2SO4.
1) Molar mass of sodium hydroxide: 23 + 16 + 1 = 40.
2) The amount of sodium hydroxide substance is: 16/40 = 0.4 mol.
3) Molar mass of copper sulfate: 64 + 32 + 64 = 160.
4) The amount of copper sulfate substance is: 16/160 = 0.1 mol.
Lack of copper sulfate. The calculation is carried out on it.
5) Molar mass of copper hydroxide: 64 + 32 + 2 = 98.
6) Find the mass of copper hydroxide. To do this, we multiply the amount of copper hydroxide substance by its molar mass: 98 * 0.1 = 9.8 g – the answer.



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