What is the mass of copper oxide reacting with sulfuric acid if you received 40 grams of copper sulfate?

Given:

m (CuSO4) = 40 g;

To find:

m (CuO) -?

Decision:

1) We compose the reaction equation typical for the condition of the given problem:

CuO + H2SO4 = CuSO4 + H2O;

2) Find the amount of copper sulfate contained in 40 grams of salt:

n (CuSO4) = m: M = 40 g: 160 g / mol = 0.25 mol;

3) We compose logical equality:

if 1 mol of CuO gives 1 mol of CuSO4,

then x mol CuO will give 0.25 mol CuSO4,

then x = 0.25 mol.

4) Find the mass of copper oxide that has reacted:

m (CuO) = n * M = 0.25 mol * 80 g / mol = 20 g;

Answer: m (CuO) = 20 g.