What is the mass of copper sulfate, which can be obtained from 32 g of copper oxide if it is treated with 8 ml of 5% sulfuric

What is the mass of copper sulfate, which can be obtained from 32 g of copper oxide if it is treated with 8 ml of 5% sulfuric acid solution with a density of 1.03 g / cm3

1) Let’s compose the reaction equation
CuO + H2SO4 = CuSO4 + H2O

2) Find a flaw in this reaction
n (CuO) = 32g / 80g / mol = 0.4 mol (e)
n (H2SO4) = (8 * 0.05 * 1.03) / 98 = 0.004 mol (week)

3) Determine the mass of copper sulphate by a drawback
m (CuSO4) = 0.004 mol * 160g / mol = 0.64g
Answer: m (CuSO4) = 0.64g