What is the mass of ethylene glycol obtained as a result of alkaline hydrolysis of 56.4 g of 1,2-dibromoethane?

Given:
m (C2H4Br2) = 56.4 g

To find:
m (C2H6O2) -?

Decision:
1) CH2Br-CH2Br + 2NaOH => CH2OH-CH2OH + 2NaBr;
2) n (C2H4Br2) = m (C2H4Br2) / M (C2H4Br2) = 56.4 / 188 = 0.3 mol;
3) n (C2H6O2) = n (C2H4Br2) = 0.3 mol;
4) m (C2H6O2) = n (C2H6O2) * M (C2H6O2) = 0.3 * 62 = 18.6 g.

Answer: The mass of C2H6O2 is 18.6 g.



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