What is the mass of forginseed lime formed when calculating 10 kg of limestone containing 10% impurities?

Perform a solution:

Under the condition of the problem, we will make the equation of the calcination process:
Caco3 = Cao + H2O – decomposition, obtained calcium oxide (forgery);

Producing calculations:
M (Caco3) = 100 g / mol;

M (CaO) = 56 g / mol;

M (Caco3) = 10,000 * (1 – 0.10) = 9000 g = 9 kg (weight without impurities).

We define the amount of starting material:
Y (Caco3) = m / m = 9000/100 = 90 mole;

Y (Cao) = 90 mole Since the amount of substances is 1 mol.

We find a lot of product:
M (CaO) = y * m = 90 * 56 = 2040 g

Answer: Mass of the oversized lime is 2040 g