To solve the problem, it is necessary to create a condition.
w (HCl) – 35% (mass fraction of hydrochloric acid)
m solution of hydrochloric acid (HCl) – 200 grams,
m (HCL) -?
(mass of hydrochloric acid in solution).
m substance = m p-pа * w / 100%
m in-va (HCL) = 200 gr * 35% / 100% = 70 grams,
Answer: the mass of the substance of hydrochloric acid in solution is 70 grams.
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