What is the mass of iron (3) oxide formed during the decomposition of 214 g of iron (3) hydroxide?

1. Let’s compose the equation of the chemical reaction.

2Fe (OH) 3 = Fe2O3 + 3H2O.

2. Find the amount of the substance of iron (III) hydroxide.

n (Fe (OH) 3) = m (Fe (OH) 3) / M (Fe (OH) 3) = 214 g / 107 g / mol = 2 mol.

3. Using the written reaction equation, we determine the mass of iron oxide (III).

n (Fe2O3) = n (Fe (OH) 3) / 2 = 2 mol / 2 = 1 mol.

m (Fe2O3) = n (Fe2O3) * M (Fe2O3) = 1 mol * 160 g / mol = 160 g.

Answer: m (Fe2O3) = 160 g.



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