1. Let us write down the reaction equation for obtaining iron sulfide (2):
Fe + S = FeS;
2.Calculate the chemical amount of iron:
n (Fe) = m (Fe): M (Fe) = 112: 56 = 2 mol;
3.The amounts of sulfide and iron according to the equation are related as 1: 1:
n (FeS) = n (Fe) = 2 mol;
4.Let’s find the mass of the resulting iron sulfide:
m (FeS) = n (FeS) * M (FeS);
M (FeS) = 56 + 32 = 88 g / mol;
m (FeS) = 2 * 88 = 176 g.
Answer: 176 g.
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