What is the mass of lead if 50 kJ of heat is transferred to the surrounding air during its solidification?

We need to find: m
Given:
Q = 50kJ
Lambda = 0.59 × 10 * 5 (ten in the fifth) J / kg
The system is international:
50000J
59000j / kg
m = Q / lambda
m = 50,000 / 59,000≈0.85 kg or 850g
Answer: 850g



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