What is the mass of lead if, when it is cooled from the crystallization temperature to 27C, an amount

What is the mass of lead if, when it is cooled from the crystallization temperature to 27C, an amount of heat of 156000 J is released?

To calculate the value of the mass of cooled lead, we apply the formula: Q = Cc * m * (tcr – tc), whence we express: m = Q / (Cc * (tcr – tc)).

Variables and constants: Q – released heat (Q = 156000 J); Сс – specific heat (Сс = 140 J / (kg * K)); tcr – crystallization temperature (tcr = 327.4 ºС ≈ 327 ºС); tк – final temperature (tк = 27 ºС).

Calculation: m = Q / (Cc * (tcr – tc)) = 156000 / (140 * (327 – 27)) = 3.71 kg.

Answer: The mass of cooled lead is 3.71 kg.



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