1. The interaction of lithium with sulfuric acid proceeds according to the equation:
2Li + H2SO4 = Li2SO4 + H2 ↑;
2.Calculate the chemical amount of released hydrogen:
n (H2) = V (H2): Vm = 2.24: 22.4 = 0.1 mol;
3.the stoichiometric coefficients of lithium and hydrogen in the equation are related as 2: 1, we determine the amount of lithium:
n (Li) = n (H2) * 2 = 0.1 * 2 = 0.2 mol;
4.Calculate the mass of the interacting lithium:
m (Li) = n (Li) * M (Li) = 0.2 * 7 = 1.4 g.
Answer: 1.4 g.
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