What is the mass of magnesium oxide formed by the interaction of 48 g of magnesium with oxygen

What is the mass of magnesium oxide formed by the interaction of 48 g of magnesium with oxygen, if the practical yield from theoretically possible was 85%

Magnesium is oxidized very intensively by oxygen. This reaction is described by the following equation:

Mg + ½ O2 = MgO;

During oxidation, one oxygen atom is attached to the magnesium atom. In this case, one molecule of magnesium oxide is synthesized.

Let’s determine the chemical amount of magnesium.

To do this, divide the available weight of magnesium by the weight of 1 mole of this substance.

M Mg = 24 grams / mol; N Mg = 48/24 = 2 mol;

During the reaction, the same amount of magnesium oxide will be synthesized.

Let’s determine its weight.

Let’s multiply the molar amount of the substance and the weight of 1 mole of the substance.

M MgO = 24 + 16 = 40 grams / mol; m MgO = 2 x 40 = 80 grams;

Taking into account the reaction yield of 85%, the mass of magnesium oxide will be 80 x 0.85 = 68 grams;



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