What is the mass of mercury (Hg) obtained from 4 moles of mercury oxide (HgO)?

n (HgO) = 4 mol
To find:
m (Hg)
2HgO = 2Hg + O2
n (HgO): n (Hg) = 1: 1
n (Hg) = 4 mol
m (Hg) = n * M = 4 mol * 201 g / mol = 804 g
Answer: 804 g

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