What is the mass of oxide formed by the interaction of 300 grams of calcium with oxygen?

Calcium enters into an oxidation reaction with oxygen. This reaction is described by the following chemical reaction equation:
Ca + ½ O2 = CaO;
During oxidation, one oxygen atom is attached to the calcium atom. During the reaction, one calcium oxide molecule is synthesized.
Let’s define the chemical (molar) amount of calcium.
Divide the available weight of calcium by the weight of 1 mole of this substance.
M Ca = 40 grams / mol; N Ca = 300/40 = 7.5 mol;
The same amount of calcium oxide will be synthesized.
Let’s determine its weight.
N CaO = 7.5 mol; M CaO = 40 +16 = 56 grams / mol; m CaO = 7.5 x 56 = 420 grams



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