What is the mass of propionic acid obtained by oxidation of 25 liters. aldehyde, if the product yield 92%?

Let’s execute the solution:
1. In accordance with the condition of the problem, we compose the equation:
V = 25 HP X g -? W = 92%
Н3С – СН2 – СОН + Ag2O = H3C – CH2 – COOH + 2Ag – oxidation of aldehyde with silver oxide, propionic acid was obtained;
2. Calculation:
M (C3H6O) = 58 g / mol;
M (C3H6O2) = 74 g / mol.
3. Determine the amount of starting material and product:
1 mol of gas at normal level – 22.4 liters;
X mol (С3Н6О) -25 l. hence, X mol (C3H6O) = 1 * 25 / 22.4 = 1.12 mol.
Y (C3H6O2) = 1.12 l. since the amount of substances according to the equation is 1 mol.
4. Find the mass of the product:
m (C3H6O) = Y * M = 1.12 * 74 = 82.88 g.
m (practical) = 0.92 * 82.88 = 76.25 g.
Answer: propionic acid was obtained with a mass of 76.25 g.