# What is the mass of silver released during the oxidation of 230 g of glucose containing 11% impurities

January 15, 2021 | education

| **What is the mass of silver released during the oxidation of 230 g of glucose containing 11% impurities if an ammonia solution of silver oxide (Ag2o) serves as an oxidizing agent.**

1. We make a chemical equation, not forgetting to put down the coefficients:

C6H12O6 + Ag2O = CH2OH – (CHOH) 4 – COOH + 2Ag.

2. Find the mass of C6H12O6:

m (C6H12O6) = 180 g / mol * 1 mol = 180g.

3. Find the mass Ag:

m (Ag) = 108 g / mol * 2 mol = 216 g.

4. Find the mass of impurities:

m (impurities) = 11% * 230g / 100% = 25.3g.

5. Find the mass of glucose:

m (glucose) = 230g – 25.3g = 204.7g.

6.Using the equation, compose the proportion and find the mass of silver:

204.7g / 180g = Xg / 216g.

m (Ag) = 204.7g * 216g / 180g = 245.64g.

Answer: m (Ag) = 245.64g.

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