What is the mass of the ester formed when acetic acid weighs 100 g on ethanol weighs 69 g?

1. Let us write the equation of the reaction between acetic acid and ethanol:

CH3COOH + C2H5OH → CH3COOC2H5 + H2O;

2. find the chemical amount of acetic acid:

n (CH3COOH) = m (CH3COOH): M (CH3COOH);

M (CH3COOH) = 12 + 3 + 12 + 32 + 1 = 60 g / mol;

n (CH3COOH) = 100: 60 = 1.67 mol;

3.Calculate the amount of ethanol:

n (C2H5OH) = m (C2H5OH): M (C2H5OH);

M (C2H5OH) = 2 * 12 + 5 + 17 = 46 g / mol;

n (C2H5OH) = 69: 46 = 1.5 mol;

4.1.5 <1.67, it means that ethanol was taken in the lack, we determine the amount of the formed ether:

n (CH3COOC2H5) = n (C2H5OH) = 1.5 mol;

5.Calculate the mass of ethyl acetate:

m (CH3COOC2H5) = n (CH3COOC2H5) * M (CH3COOC2H5);

M (CH3COOC2H5) = 12 + 3 + 12 + 32 + 24 + 5 = 88 g / mol;

m (CH3COOC2H5) = 1.5 * 88 = 132 g.

Answer: 132 g.