What is the mass of the formed salt, if it is known that a solution of sulfuric acid

What is the mass of the formed salt, if it is known that a solution of sulfuric acid weighing 50 g was taken for the reaction with zinc, with a mass fraction of acid in it equal to 98%?

To solve, we write down the process according to the condition of the problem:
m = 50 g; W = 98% X g -?
1. Zn + H2SO4 = ZnSO4 + H2 – substitutions, zinc sulfate salt, hydrogen was obtained;
2. Let’s make calculations using the formulas:
M (H2SO4) = 98 g / mol.
M (ZnSO4) = 161.3 g / mol.
3. W = m (practical) / m (theoretical) * 100;
m (practical) = 50 / 0.98 = 51.02 g (mass of acid).
4. Determine the amount of H2SO4:
Y (H2SO4) = m / M = 51.02 / 98 = 0.52 mol.
5. Find the mass of the product:
m (ZnSO4) = Y * M = 0.52 * 161.3 = 83.88 g.
Answer: the mass of zinc sulfate is 83.88 g.