What is the mass of the solute in the solution obtained by draining 160 g of a solution with

What is the mass of the solute in the solution obtained by draining 160 g of a solution with a mass fraction of 5% salt and 240 g of a solution with a mass fraction of 10%?

Let’s find the mass of water and substance in the first solution:

The mass of the solution is 160 grams;

To find the mass of salt, it is necessary to multiply its mass fraction by the mass of the solution.

m of substance 1 = 160 x 0.05 = 8 grams;

To find the mass of water, subtract the mass of salt from the mass of the solution:

m of water 1 = 160 – 8 = 152 grams;

Check: 152 + 8 = 160;

Let’s find the mass of water and substance in the second solution:

The mass of the solution is 160 grams;

To find the mass of salt, it is necessary to multiply its mass fraction by the mass of the solution.

m of substance 2 = 240 x 0.1 = 24 grams;

To find the mass of water, subtract the mass of salt from the mass of the solution:

m of water 2 = 240 – 24 = 216 grams;

Check: 216 + 24 = 240;

Let’s find the total mass of water and substance in the new solution:

m of substance = 8 + 24 = 32 grams;

m of water = 152 + 216 = 368 grams;

The mass fraction of the substance in the new solution will be:

K = 32 / (368 + 32) = 0.08 = 8%